The four quantum numbers of distiguished electron of an atom are as follow begin{tabular}{|l|l|l|l|} hline ( mathrm{n} ) & ( l ) & ( mathrm{~m}_{l} ) & ( mathrm{~m}_{mathrm{s}} ) hline 2 & 1 & 0 & ( +frac{1}{2} ) hline end{tabular} Using the above information answer the following questions. i) How many electrons present in outer most orbit? ii) Write the electron configuration of this element? iii) What is the atomic number of this element? iv) What is the shape of the last electron orbital?
Question
The four quantum numbers of distiguished electron of an atom are as follow begin{tabular}{|l|l|l|l|} hline ( mathrm{n} ) & ( l ) & ( mathrm{~m}{l} ) & ( mathrm{~m}{mathrm{s}} ) hline 2 & 1 & 0 & ( +frac{1}{2} ) hline end{tabular} Using the above information answer the following questions. i) How many electrons present in outer most orbit? ii) Write the electron configuration of this element? iii) What is the atomic number of this element? iv) What is the shape of the last electron orbital?
Solution
i) The outermost orbit of an atom is determined by the principal quantum number (n). In this case, n=2, which means the outermost orbit can hold a maximum of 2n^2 = 2*(2^2) = 8 electrons.
ii) The electron configuration of an element is determined by the quantum numbers. Here, n=2 and l=1. The value of l=1 corresponds to the p orbital. So, the electron configuration is 1s^2 2s^2 2p^1.
iii) The atomic number of an element is equal to the total number of electrons in an atom. From the electron configuration, we can see that there are 5 electrons. So, the atomic number of this element is 5, which corresponds to Boron.
iv) The shape of the last electron orbital is determined by the azimuthal quantum number (l). Here, l=1, which corresponds to a p orbital. The shape of a p orbital is dumbbell-shaped.
Similar Questions
The four quantum numbers of distiguished electron of an atom are as follow begin{tabular}{|l|l|l|l|} hline ( mathrm{n} ) & ( l ) & ( mathrm{~m}_{l} ) & ( mathrm{~m}_{mathrm{s}} ) hline 2 & 1 & 0 & ( +frac{1}{2} ) hline end{tabular} Using the above information answer the following questions. i) How many electrons present in outer most orbit? ii) Write the electron configuration of this element? iii) What is the atomic number of this element? iv) What is the shape of the last electron orbital?
In an atom, total number of electrons having quantum numbers n=4,| ml|=1n=4,| m𝑙|=1 and ms=−12ms=−12 is______
Complete the table below by filling in the principal quantum number n and angular momentum quantum number l for each electron subshell listed.subshell principalquantum number n angular momentumquantum number l6s 5p 4f 3d
The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. List if any of these combination(s) has/have the same energy(i) n = 4, l = 2, ml = -2, ms = -1/2(ii) n = 3, l = 2, ml = 1, ms = +1/2(iii) n = 4, l = 1, ml = 0, ms = +1/2(iv) n = 3, l = 2, ml = -2, ms = -111(v) n = 3, l = l, ml = -1, ms = +1/2(vi) n = 4, l = 1, ml = 0, ms = +1/2
The correct set of four quantum numbers for the valence electron of K atom is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.