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What does this code print?void print(int nb){ printf("%d", nb); nb ++; if (nb < 10) { print(nb); }}int main(void){ print(4); return (0);}

Question

What does this code print?void print(int nb){ printf("%d", nb); nb ++; if (nb < 10) { print(nb); }}int main(void){ print(4); return (0);}

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Solution

This code will print the numbers from 4 to 9. Here's how it works:

  1. The main function calls the print function with the argument 4.
  2. The print function prints the number 4 and then increments nb by 1, making nb equal to 5.
  3. The if statement checks if nb is less than 10. Since 5 is less than 10, the print function is called again with nb equal to 5.
  4. This process repeats, with nb incrementing by 1 each time, until nb is equal to 10. At this point, the if statement is no longer true, so the print function stops being called.
  5. The main function then returns 0, ending the program.

So, the output of this code will be 456789.

This problem has been solved

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