What will be the output of the following Java program?class output_odd { public static void main(String args[]) { int p = 2; int q = 0; for ( ; q < 8; ++q) { if (q % p == 0) continue; else if (q == 6) break; else System.out.print(q + " "); } } }Options2 4 6 81 3 5 7 91 3 5 71 2 3 4 5 6 7 8 9
Question
What will be the output of the following Java program?class output_odd { public static void main(String args[]) { int p = 2; int q = 0; for ( ; q < 8; ++q) { if (q % p == 0) continue; else if (q == 6) break; else System.out.print(q + " "); } } }Options2 4 6 81 3 5 7 91 3 5 71 2 3 4 5 6 7 8 9
Solution
The output of the given Java program will be "1 3 5 ".
Here's the step by step explanation:
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The program starts with the initialization of two integer variables, p and q, with values 2 and 0 respectively.
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Then, a for loop is started where the condition is q < 8. The loop will continue until the value of q is less than 8.
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Inside the loop, there is an if condition that checks if the remainder of q divided by p is equal to 0. If it is, the loop will continue to the next iteration without executing the rest of the code inside the loop. This means that it will skip all even numbers because when an even number is divided by 2, the remainder is 0.
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If the remainder of q divided by p is not 0 (which means q is an odd number), it will check the next condition, which is if q is equal to 6. If it is, it will break the loop and stop the execution. But in this case, 6 will not be printed because 6 is an even number and the first condition (q % p == 0) will be true, so it will continue to the next iteration without checking the rest of the conditions.
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If q is not equal to 6, it will print the value of q and a space. This will print all odd numbers less than 8.
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The loop will increment the value of q by 1 in each iteration (++q).
So, the output will be the odd numbers less than 8, which are 1, 3, and 5.
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