The correct answer is 10.

Here's the step-by-step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there's an if statement that checks if w is equal to x shifted right by 1. The right shift operator () in Java shifts the bits of the number to the right and fills 0 on voids left as a result. The right shift by 1 of x (which is 10 in binary form 1010) results in 5 (in binary form 101). So, the condition w == x 1 is true.

4. When the condition is true, the break statement is executed. The break statement with a label (in this case, second) breaks the labeled block. So, the control goes out of the second block.

5. The statement System.out.println(w); inside the second block is not executed because the control has already moved out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints 10.

7. Therefore, the output of the program is 10.

Question

The correct answer is 10.

Here's the step-by-step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there's an if statement that checks if w is equal to x shifted right by 1. The right shift operator (>>) in Java shifts the bits of the number to the right and fills 0 on voids left as a result. The right shift by 1 of x (which is 10 in binary form 1010) results in 5 (in binary form 101). So, the condition w == x >> 1 is true.

4. When the condition is true, the break statement is executed. The break statement with a label (in this case, second) breaks the labeled block. So, the control goes out of the second block.

5. The statement System.out.println(w); inside the second block is not executed because the control has already moved out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints 10.

7. Therefore, the output of the program is 10.

Knowee AI · Accepted Answer

The correct answer is 10.

Here's the step-by-step explanation:

1. The program starts with the declaration of two integer variables, w and x, with values 5 and 10 respectively.

2. Then, there are three labeled blocks: first, second, and third.

3. Inside the third block, there's an if statement that checks if w is equal to x shifted right by 1. The right shift operator (>>) in Java shifts the bits of the number to the right and fills 0 on voids left as a result. The right shift by 1 of x (which is 10 in binary form 1010) results in 5 (in binary form 101). So, the condition w == x >> 1 is true.

4. When the condition is true, the break statement is executed. The break statement with a label (in this case, second) breaks the labeled block. So, the control goes out of the second block.

5. The statement System.out.println(w); inside the second block is not executed because the control has already moved out of the second block due to the break statement.

6. The next statement is System.out.println(x); which is outside the second block. So, it is executed and prints 10.

7. Therefore, the output of the program is 10.

Select the correct answerWhat will be the output of the following Java program?class java { public static void main(String args[]) { int w = 5; int x = 10; first: { second: { third: { if (w == x >> 1) break second; } System.out.println(w); } System.out.println(x); } } }Options5 1051010 5

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