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What will be the output of the following Java program? class array_value { public static void main(String args[]) { int array_variable [] = new int[20]; for (int v = 10; v < 20; ++v) { array_variable[v] = v/2; array_variable[v]++; System.out.print(array_variable[v] + " "); v++; }  } }Options6 7 8 9 1010 12 14 16 1810 11 12 13 14 15 16 17 18 1910 11 12 13 14 15 16 17 18 19 20

Question

What will be the output of the following Java program? class array_value { public static void main(String args[]) { int array_variable [] = new int[20]; for (int v = 10; v < 20; ++v) { array_variable[v] = v/2; array_variable[v]++; System.out.print(array_variable[v] + " "); v++; }  } }Options6 7 8 9 1010 12 14 16 1810 11 12 13 14 15 16 17 18 1910 11 12 13 14 15 16 17 18 19 20

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Solution

The output of the given Java program will be "6 7 8 9 10".

Here's the step-by-step explanation:

  1. An integer array named array_variable of size 20 is declared.

  2. A for loop is initiated where the variable v starts from 10 and goes up to 19 (since the condition is v < 20).

  3. Inside the loop, the vth element of the array is assigned the value of v/2. Since v is an integer, this will be integer division, so the decimal part will be discarded. For example, when v is 10, v/2 will be 5.

  4. The vth element of the array is then incremented by 1, so it becomes v/2 + 1.

  5. This value is then printed out, followed by a space.

  6. The variable v is incremented again at the end of the loop.

  7. This process repeats until v is no longer less than 20.

So, the output will be "6 7 8 9 10", which corresponds to the values of v/2 + 1 for v equal to 10, 12, 14, 16, and 18.

This problem has been solved

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