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๐‘†๐‘ข๐‘๐‘๐‘œ๐‘ ๐‘’ย ๐‘กโ„Ž๐‘Ž๐‘กย ๐‘กโ„Ž๐‘’ย ๐‘โ„Ž๐‘Ž๐‘Ÿ๐‘Ž๐‘๐‘ก๐‘’๐‘Ÿ๐‘–๐‘ ๐‘ก๐‘–๐‘ย ๐‘๐‘œ๐‘™๐‘ฆ๐‘›๐‘œ๐‘š๐‘–๐‘Ž๐‘™ย ๐‘œ๐‘“ย ๐‘ ๐‘œ๐‘š๐‘’ย ๐‘š๐‘Ž๐‘ก๐‘Ÿ๐‘–๐‘ฅย ๐ดย ๐‘–๐‘ ย ๐‘“๐‘œ๐‘ข๐‘›๐‘‘ย ๐‘ก๐‘œย ๐‘๐‘’ย ๐‘(๐œ†)ย =ย (๐œ†ย -ย 1)๐œ†ย -32ย ย ๐œ†ย -43ย ย .ย ๐‘Šโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘กโ„Ž๐‘’ย ๐‘ ๐‘–๐‘ง๐‘’ย ๐‘œ๐‘“ย ๐ด?

Question

๐‘†๐‘ข๐‘๐‘๐‘œ๐‘ ๐‘’ย ๐‘กโ„Ž๐‘Ž๐‘กย ๐‘กโ„Ž๐‘’ย ๐‘โ„Ž๐‘Ž๐‘Ÿ๐‘Ž๐‘๐‘ก๐‘’๐‘Ÿ๐‘–๐‘ ๐‘ก๐‘–๐‘ย ๐‘๐‘œ๐‘™๐‘ฆ๐‘›๐‘œ๐‘š๐‘–๐‘Ž๐‘™ย ๐‘œ๐‘“ย ๐‘ ๐‘œ๐‘š๐‘’ย ๐‘š๐‘Ž๐‘ก๐‘Ÿ๐‘–๐‘ฅย ๐ดย ๐‘–๐‘ ย ๐‘“๐‘œ๐‘ข๐‘›๐‘‘ย ๐‘ก๐‘œย ๐‘๐‘’ย ๐‘(๐œ†)ย =ย (๐œ†ย -ย 1)๐œ†ย -32ย ย ๐œ†ย -43ย ย .ย ๐‘Šโ„Ž๐‘Ž๐‘กย ๐‘–๐‘ ย ๐‘กโ„Ž๐‘’ย ๐‘ ๐‘–๐‘ง๐‘’ย ๐‘œ๐‘“ย ๐ด?

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Solution

The characteristic polynomial of a matrix is given by the determinant of (ฮปI - A), where I is the identity matrix, A is the matrix in question, and ฮป are the eigenvalues. The degree of this polynomial is equal to the size of the matrix.

In the given polynomial p(ฮป) = (ฮป - 1)ฮป -32 ฮป -43, we can see that the highest power of ฮป is 3. Therefore, the size of the matrix A is 3x3.

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๐‘“(๐‘ฅ) = ๐‘ฅ3 + 3๐‘ฅ โˆ’ 4

Find lim๐‘ฅโ†’1 ๐‘“(๐‘ฅ), where๐‘“(๐‘ฅ) { ๐‘ฅ2 โˆ’ 1, ๐‘ฅ โ‰ค 1โˆ’๐‘ฅ2 โˆ’ 1, ๐‘ฅ > 1

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๐‘“(๐‘ฅ) = ๐‘ฅ4 โˆ’ 4๐‘ฅ3 + 4๐‘ฅ2

The expressionย  (4๐‘ฅ13๐‘ฆโˆ’1)32(๐‘ฅ๐‘ฆ)52 can be written in the form ๐‘ร—๐‘ฅ๐‘žร—๐‘ฆ๐‘Ÿ, where ๐‘,๐‘ž,๐‘Ÿ are integers. What is ๐‘+๐‘ž+๐‘Ÿ ? (Give only the numberย as your answer.)

1/3

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