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๐‘“(๐‘ฅ) = ๐‘ฅ4 โˆ’ 4๐‘ฅ3 + 4๐‘ฅ2

Question

๐‘“(๐‘ฅ) = ๐‘ฅ4 โˆ’ 4๐‘ฅ3 + 4๐‘ฅ2

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If lim๐‘ฅโ†’2๐‘“(๐‘ฅ)=3๐‘ฅ and lim๐‘ฅโ†’2๐‘”(๐‘ฅ)=4๐‘ฅ2โˆ’5, what is lim๐‘ฅโ†’2๐‘”(๐‘“(๐‘ฅ))?

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