Instructions: Given the quadratic function, find the x𝑥-value of the vertex (axis of symmetry).y=x2+4x−8
Question
Instructions: Given the quadratic function, find the x𝑥-value of the vertex (axis of symmetry).y=x2+4x−8
Solution
The vertex form of a quadratic function is given by y = a(x-h)² + k, where (h, k) is the vertex of the parabola.
The x-value of the vertex (h) can be found using the formula h = -b/2a.
In the given quadratic function y = x² + 4x - 8, the coefficient a is 1 and the coefficient b is 4.
Substituting these values into the formula, we get:
h = -b/2a = -4/(2*1) = -2
So, the x-value of the vertex of the given quadratic function is -2.
Similar Questions
Instructions: Given the vertex of a quadratic function, find the axis of symmetry.Vertex: (3,4)
Instructions: Given the function, state the vertex.y=−3(x+4)2−8
Select the correct answer.Select the quadratic function with a graph that has the following features.x-intercept at (8,0)y-intercept at (0,-32)maximum value at (6,4)axis of symmetry at x = 6
Instructions: For the following quadratic functions, write the function in factored form and then find the x𝑥-intercepts, axis of symmetry, vertex, and domain and range.y=x2+4x+3𝑦=𝑥2+4𝑥+3Factored Form: y=(x𝑦=(𝑥 Answer 1 Question 4 Answer 2 Question 4 )(x)(𝑥 Answer 3 Question 4 Answer 4 Question 4 )) (Type least to greatest.)x𝑥-Intercepts: (( Answer 5 Question 4 ,, Answer 6 Question 4 )) and (( Answer 7 Question 4 ,, Answer 8 Question 4 )) (Type least to greatest.)Axis of Symmetry: x=𝑥= Answer 9 Question 4Vertex: (( Answer 10 Question 4 ,, Answer 11 Question 4 ))Domain: Answer 12 Question 4Range: y𝑦 Answer 13 Question 4 Answer 14 Question 4
Instructions: Given the function, state the vertex.y=2(x−4)2−1
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.