What is the output of the following C code?char *ptr;char mystring[] = "abcdefg";ptr = myString;ptr += 5;
Question
What is the output of the following C code?char *ptr;char mystring[] = "abcdefg";ptr = myString;ptr += 5;
Solution
The output of the given code is not specified as it does not contain any code to print or display the value of the variable ptr. However, I can explain what the code does step by step:
- Declare a character pointer variable
ptr. - Declare a character array
mystringand initialize it with the string "abcdefg". - Assign the starting address of
mystringto the pointer variableptr. - Increment the pointer
ptrby 5 positions.- After this step,
ptrwill point to the 6th character in themystringarray, which is the character 'g'.
- After this step,
To see the output, you would need to add code to print or display the value of ptr, such as printf("%c", *ptr);.
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