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1.What is the output of the following code?char str[] = "hello";printf("%c\n", str[1]);

Question

1.What is the output of the following code?char str[] = "hello";printf("%c\n", str[1]);

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Solution

The output of the code will be 'e'.

Here's the step by step explanation:

  1. The code declares a character array str[] and initializes it with the string "hello".

  2. In C and C++, strings are actually one-dimensional array of characters terminated by a null character '\0'. So the string "hello" is stored in the array like this: 'h', 'e', 'l', 'l', 'o', '\0'.

  3. Array indexing in C and C++ starts from 0. So, str[0] is 'h', str[1] is 'e', str[2] is 'l', and so on.

  4. The printf function is used to print the character at index 1 of the array, which is 'e'. So, 'e' will be the output of the code.

This problem has been solved

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