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A can do 2/5 of a work in 12 days while B can do 66 2/3% of the same work in 16 days. They work together for 10 days. B alone will complete the remaining work in?Options6498

Question

A can do 2/5 of a work in 12 days while B can do 66 2/3% of the same work in 16 days. They work together for 10 days. B alone will complete the remaining work in?Options6498

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Solution

Sure, let's solve this step by step:

  1. First, let's find out how much work A and B can do in one day.

    A can do 2/5 of the work in 12 days, so in one day, A can do (2/5)/12 = 1/30 of the work.

    B can do 66 2/3% of the work in 16 days. 66 2/3% is equivalent to 2/3 in fraction. So, in one day, B can do (2/3)/16 = 1/24 of the work.

  2. Now, let's find out how much work they can do together in one day.

    A and B together can do 1/30 + 1/24 = 4/120 + 5/120 = 9/120 = 3/40 of the work in one day.

  3. They work together for 10 days, so in 10 days, they can do 10 * 3/40 = 3/4 of the work.

  4. The remaining work is 1 - 3/4 = 1/4.

  5. Now, let's find out how many days B will take to complete the remaining work.

    Since B can do 1/24 of the work in one day, B will take 1/4 / 1/24 = 24/4 = 6 days to complete the remaining work.

So, B alone will complete the remaining work in 6 days. The correct option is 6.

This problem has been solved

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