A can finish one-third of a work in 5 days, B can finish 2/5th of the same work in 10 days and C can finish 75% of the same work in 15 days. They work together for 6 days; The remaining work will be finished by B alone in?Options5 days3 days2.5 days1.5 days
Question
A can finish one-third of a work in 5 days, B can finish 2/5th of the same work in 10 days and C can finish 75% of the same work in 15 days. They work together for 6 days; The remaining work will be finished by B alone in?Options5 days3 days2.5 days1.5 days
Solution
To solve this problem, we first need to find out how much work each person can do in one day.
- A can finish 1/3 of the work in 5 days, so in one day, A can do 1/3 ÷ 5 = 1/15 of the work.
- B can finish 2/5 of the work in 10 days, so in one day, B can do 2/5 ÷ 10 = 1/25 of the work.
- C can finish 75% (or 3/4) of the work in 15 days, so in one day, C can do 3/4 ÷ 15 = 1/20 of the work.
When they work together, in one day they can do 1/15 + 1/25 + 1/20 = 0.12 of the work.
So, in 6 days, they can do 6 * 0.12 = 0.72 (or 72%) of the work.
This means that 28% of the work is left.
Since B can do 1/25 of the work in one day, to do the remaining 28% of the work, B will need 0.28 ÷ (1/25) = 7 days.
So, the remaining work will be finished by B alone in 7 days. However, this option is not available in the given options. Please check the problem statement again.
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