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There are two boxes containing only purple and yellow pens.Box A has 8 yellow pens and 8 purple pens.Box B has 9 yellow pens and 11 purple pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a purple pen from Box B.Event 2: choosing a yellow pen from Box B.Event 3: choosing a yellow or purple pen from Box A.Event 4: choosing a yellow pen from Box A.Least likely Most likelyEvent ,  Event ,  Event ,  Event

Question

There are two boxes containing only purple and yellow pens.Box A has 8 yellow pens and 8 purple pens.Box B has 9 yellow pens and 11 purple pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a purple pen from Box B.Event 2: choosing a yellow pen from Box B.Event 3: choosing a yellow or purple pen from Box A.Event 4: choosing a yellow pen from Box A.Least likely Most likelyEvent ,  Event ,  Event ,  Event

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Solution

To answer this question, we first need to calculate the probability of each event:

Event 1: The probability of choosing a purple pen from Box B. There are 20 pens in total in Box B (9 yellow + 11 purple). So, the probability is 11/20 = 0.55.

Event 2: The probability of choosing a yellow pen from Box B. There are 20 pens in total in Box B (9 yellow + 11 purple). So, the probability is 9/20 = 0.45.

Event 3: The probability of choosing a yellow or purple pen from Box A. Since all pens in Box A are either yellow or purple, the probability of this event is 1 (or 100%).

Event 4: The probability of choosing a yellow pen from Box A. There are 16 pens in total in Box A (8 yellow + 8 purple). So, the probability is 8/16 = 0.5.

Now, we can list these events from least likely to most likely:

Least likely: Event 2 (choosing a yellow pen from Box B) Next: Event 1 (choosing a purple pen from Box B) Next: Event 4 (choosing a yellow pen from Box A) Most likely: Event 3 (choosing a yellow or purple pen from Box A)

This problem has been solved

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