A box contains 9 white 4 black and 7 red pens. Three pens are selected in succession without replacement. What is the probability if the first pen is red, second is black and third is also red
Question
A box contains 9 white 4 black and 7 red pens. Three pens are selected in succession without replacement. What is the probability if the first pen is red, second is black and third is also red
Solution
To find the probability of selecting a red pen first, a black pen second, and another red pen third, we need to calculate the probability of each event happening and then multiply them together.
Step 1: Calculate the probability of selecting a red pen first. There are a total of 20 pens in the box, and 7 of them are red. Therefore, the probability of selecting a red pen first is 7/20.
Step 2: Calculate the probability of selecting a black pen second. After the first pen is selected, there are now 19 pens left in the box. Out of these, 4 are black. Therefore, the probability of selecting a black pen second is 4/19.
Step 3: Calculate the probability of selecting another red pen third. After the first two pens are selected, there are now 18 pens left in the box. Out of these, 6 are red. Therefore, the probability of selecting another red pen third is 6/18, which simplifies to 1/3.
Step 4: Multiply the probabilities together. To find the overall probability, we multiply the probabilities of each event together: (7/20) * (4/19) * (1/3) = 28/1140 = 7/285.
Therefore, the probability of selecting a red pen first, a black pen second, and another red pen third is 7/285.
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