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In a bag, there are 6 black pens, 4 blue pens, and 5 red pens. If three pens are drawn without replacement, what is the probability that the first pen is black, the second pen is blue, and the third pen is red?

Question

In a bag, there are 6 black pens, 4 blue pens, and 5 red pens. If three pens are drawn without replacement, what is the probability that the first pen is black, the second pen is blue, and the third pen is red?

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Solution

Sure, here's how you can calculate the probability:

Step 1: Calculate the total number of pens. We have 6 black pens, 4 blue pens, and 5 red pens. So, the total number of pens is 6 + 4 + 5 = 15 pens.

Step 2: Calculate the probability of drawing a black pen first. There are 6 black pens out of a total of 15 pens. So, the probability is 6/15.

Step 3: Now, one pen has been drawn, so there are only 14 pens left. Calculate the probability of drawing a blue pen next. There are 4 blue pens out of a total of 14 pens. So, the probability is 4/14.

Step 4: Now, two pens have been drawn, so there are only 13 pens left. Calculate the probability of drawing a red pen next. There are 5 red pens out of a total of 13 pens. So, the probability is 5/13.

Step 5: The final step is to multiply these three probabilities together to get the overall probability of drawing a black pen, then a blue pen, then a red pen. So, the overall probability is (6/15) * (4/14) * (5/13) = 0.033.

So, the probability that the first pen is black, the second pen is blue, and the third pen is red is 0.033 or 3.3%.

This problem has been solved

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