y=2x 2 −28x+80

It seems like there's a bit of confusion in your question. If you're asking for help with a quadratic equation, it should be in the form of y = ax^2 + bx + c.

Your equation seems to be "y = 2x^2 - 28x + 80". If you want to solve this equation for x, you can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Here, a = 2, b = -28, and c = 80.

Step 1: Calculate the value under the square root, b^2 - 4ac = (-28)^2 - 4280 = 784 - 640 = 144.

Step 2: Take the square root of 144, which is 12.

Step 3: Substitute these values into the quadratic formula to get x = [28 ± 12] / (2*2).

Step 4: Solve for x. The two possible solutions are x = (28 + 12) / 4 = 10 and x = (28 - 12) / 4 = 4.

It seems like you've made a typo in your equation. If you're trying to express a quadratic equation, it should be in the form of y = ax^2 + bx + c.

For example, if you meant y = 2x^2 - 28x + 80, then we can proceed with solving or simplifying it. Please confirm or correct the equation.