To factor the quadratic equation -2x^2 + 22x - 56 completely, follow these steps:

Step 1: Factor out the Greatest Common Factor (GCF). In this case, the GCF is -2. So, the equation becomes -2(x^2 - 11x + 28).

Step 2: Now, factor the quadratic equation inside the parentheses. We need to find two numbers that multiply to 28 and add to -11. The numbers are -4 and -7. So, the equation becomes -2(x - 4)(x - 7).

So, the completely factored form of -2x^2 + 22x - 56 is -2(x - 4)(x - 7).

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To factor the quadratic equation -2x^2 + 22x - 56 completely, follow these steps:

Step 1: Factor out the Greatest Common Factor (GCF). In this case, the GCF is -2. So, the equation becomes -2(x^2 - 11x + 28).

Step 2: Now, factor the quadratic equation inside the parentheses. We need to find two numbers that multiply to 28 and add to -11. The numbers are -4 and -7. So, the equation becomes -2(x - 4)(x - 7).

So, the completely factored form of -2x^2 + 22x - 56 is -2(x - 4)(x - 7).

Knowee AI · Accepted Answer

To factor the quadratic equation -2x^2 + 22x - 56 completely, follow these steps:

Step 1: Factor out the Greatest Common Factor (GCF). In this case, the GCF is -2. So, the equation becomes -2(x^2 - 11x + 28).

Step 2: Now, factor the quadratic equation inside the parentheses. We need to find two numbers that multiply to 28 and add to -11. The numbers are -4 and -7. So, the equation becomes -2(x - 4)(x - 7).

So, the completely factored form of -2x^2 + 22x - 56 is -2(x - 4)(x - 7).

Factor completely.minus, 2, x, squared, plus, 22, x, minus, 56−2x 2 +22x−56

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