Factor.x, squared, minus, 3, x, minus, 54x 2 −3x−54
Question
Factor.x, squared, minus, 3, x, minus, 54x 2 −3x−54
Solution 1
The expression you provided is x^2 - 3x - 54. Here are the steps to factor it:
Step 1: Identify the coefficients of the quadratic equation. In this case, a = 1 (coefficient of x^2), b = -3 (coefficient of x), and c = -54.
Step 2: Find two numbers that multiply to ac (which is -54) and add to b (which is -3). The numbers that satisfy these conditions are -9 and 6 because -96 = -54 and -9 + 6 = -3.
Step 3: Rewrite the middle term of the quadratic equation (the term involving x) as the sum of the terms -9x and 6x. This gives us x^2 - 9x + 6x - 54.
Step 4: Factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us (x^2 - 9x) + (6x - 54).
Step 5: Factor out the greatest common factor from each group. From the first group, we can factor out an x, and from the second group, we can factor out a 6. This gives us x(x - 9) + 6(x - 9).
Step 6: Notice that (x - 9) is a common factor of both terms. We can factor out (x - 9), which gives us (x - 9)(x + 6).
So, the factored form of the expression x^2 - 3x - 54 is (x - 9)(x + 6).
Solution 2
The expression you provided is x^2 - 3x - 54. Here are the steps to factor it:
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Identify the coefficients of the quadratic equation. In this case, a = 1 (coefficient of x^2), b = -3 (coefficient of x), and c = -54 (constant term).
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Look for two numbers that multiply to ac (-54) and add up to b (-3). The numbers that satisfy these conditions are -9 and 6 because -96 = -54 and -9 + 6 = -3.
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Rewrite the middle term of the quadratic equation as the sum of the terms -9x and 6x. This gives us x^2 - 9x + 6x - 54.
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Factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us x(x - 9) + 6(x - 9).
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Notice that (x - 9) is a common factor. Factor out this term to get (x - 9)(x + 6).
So, the factored form of the equation x^2 - 3x - 54 is (x - 9)(x + 6).
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