Sure! Here are the pseudo code snippets that calculate the sum of numbers from 1 to n using recursion:

Snippet 1:
```
function calculateSum(n):
if n == 1:
return 1
else:
return n + calculateSum(n-1)
```

Snippet 2:
```
function calculateSum(n):
if n == 0:
return 0
else:
return n + calculateSum(n-1)
```

Snippet 3:
```
function calculateSum(n):
if n

Question

Sure! Here are the pseudo code snippets that calculate the sum of numbers from 1 to n using recursion:

Snippet 1:
```
function calculateSum(n):
    if n == 1:
        return 1
    else:
        return n + calculateSum(n-1)
```

Snippet 2:
```
function calculateSum(n):
    if n == 0:
        return 0
    else:
        return n + calculateSum(n-1)
```

Snippet 3:
```
function calculateSum(n):
    if n <= 0:
        return 0
    else:
        return n + calculateSum(n-1)
```

Out of these three snippets, Snippet 1 and Snippet 2 correctly calculate the sum of numbers from 1 to n using recursion. Snippet 3 is incorrect because it includes the case where n is less than or equal to 0, which would result in an infinite recursion.

Knowee AI · Accepted Answer

Sure! Here are the pseudo code snippets that calculate the sum of numbers from 1 to n using recursion:

Snippet 1:
```
function calculateSum(n):
    if n == 1:
        return 1
    else:
        return n + calculateSum(n-1)
```

Snippet 2:
```
function calculateSum(n):
    if n == 0:
        return 0
    else:
        return n + calculateSum(n-1)
```

Snippet 3:
```
function calculateSum(n):
    if n <= 0:
        return 0
    else:
        return n + calculateSum(n-1)
```

Out of these three snippets, Snippet 1 and Snippet 2 correctly calculate the sum of numbers from 1 to n using recursion. Snippet 3 is incorrect because it includes the case where n is less than or equal to 0, which would result in an infinite recursion.

Which of the following pseudo code snippets correctly calculates the sum of numbers from 1 to n using recursion?

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