Using recursion, debug the following program to find 1+2+...+N, where N is obtained from user.Sample Input:4Sample Output:The result is 10
Question
Using recursion, debug the following program to find 1+2+...+N, where N is obtained from user.Sample Input:4Sample Output:The result is 10
Solution
To debug the program and calculate the sum of numbers from 1 to N using recursion, follow these steps:
-
Start by defining a function called
calculateSumthat takes an integer parameterNrepresenting the upper limit of the sum. -
Inside the
calculateSumfunction, add a base case to handle the smallest possible value of N. If N is equal to 1, return 1 as the sum. -
If the base case is not met, recursively call the
calculateSumfunction with N-1 as the argument and store the result in a variable calledpartialSum. -
Finally, return the sum of
partialSumand N.
Here is the corrected code:
def calculateSum(N):
if N == 1:
return 1
else:
partialSum = calculateSum(N-1)
return partialSum + N
# Get input from the user
N = int(input("Enter a number: "))
# Call the calculateSum function and store the result in a variable
result = calculateSum(N)
# Print the result
print("The result is", result)
Now, when you run the program and provide the input 4, it will correctly calculate the sum of numbers from 1 to 4, which is 10.
Similar Questions
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