What will be the output of the following pseudocode?1. input f=6, g=9 and set sum=02. integer n3. if ( g>f)4. for (n=f ; n<g ; n=n+1)5. sum = sum+n6. end for loop7. else8. print error message 9. print sum921156
Question
What will be the output of the following pseudocode?1. input f=6, g=9 and set sum=02. integer n3. if ( g>f)4. for (n=f ; n<g ; n=n+1)5. sum = sum+n6. end for loop7. else8. print error message 9. print sum921156
Solution
The pseudocode provided is a simple program that sums up all the integers between two given numbers, f and g, where g is greater than f. Here's how it works:
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The program starts by taking two inputs, f and g, which are 6 and 9 respectively, and initializes a variable sum to 0.
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It then checks if g is greater than f, which is true in this case (9 > 6).
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Since the condition is true, it enters a for loop where n starts from f (6) and increments by 1 until it reaches g (9).
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In each iteration of the loop, the current value of n is added to the sum.
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The loop ends when n is no longer less than g.
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If g was not greater than f, it would print an error message, but this is not the case here.
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Finally, it prints the value of sum.
So, let's calculate the sum:
- In the first iteration, n is 6, so sum becomes 0 + 6 = 6.
- In the second iteration, n is 7, so sum becomes 6 + 7 = 13.
- In the third iteration, n is 8, so sum becomes 13 + 8 = 21.
The loop ends here because the next value of n would be 9, which is not less than g.
So, the output of this pseudocode will be 21.
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