To find the total current in the circuit, we first need to find the total impedance (Z) of the circuit. Since the resistor (R), inductor (L), and capacitor (C) are connected in parallel, we can use the formula for total impedance in a parallel RLC circuit:

1/Z^2 = 1/R^2 + (1/Xl - 1/Xc)^2

where:
R = resistance = 20 Ohms
Xl = inductive reactance = 59 Ohms
Xc = capacitive reactance = 35 Ohms

Substituting these values into the formula, we get:

1/Z^2 = 1/(20)^2 + (1/59 - 1/35)^2
1/Z^2 = 0.0025 + 0.000306
1/Z^2 = 0.002806

Taking the square root of both sides to solve for Z, we get:

Z = 1/√0.002806 = 18.88 Ohms

Now that we have the total impedance, we can find the total current (I) using Ohm's law:

I = V/Z

where:
V = voltage = 120 Volts
Z = total impedance = 18.88 Ohms

Substituting these values into the formula, we get:

I = 120/18.88 = 6.36 Amps

So, the total current in the circuit is approximately 6.36 Amps.

Question

To find the total current in the circuit, we first need to find the total impedance (Z) of the circuit. Since the resistor (R), inductor (L), and capacitor (C) are connected in parallel, we can use the formula for total impedance in a parallel RLC circuit:

1/Z^2 = 1/R^2 + (1/Xl - 1/Xc)^2

where:
R = resistance = 20 Ohms
Xl = inductive reactance = 59 Ohms
Xc = capacitive reactance = 35 Ohms

Substituting these values into the formula, we get:

1/Z^2 = 1/(20)^2 + (1/59 - 1/35)^2
1/Z^2 = 0.0025 + 0.000306
1/Z^2 = 0.002806

Taking the square root of both sides to solve for Z, we get:

Z = 1/√0.002806 = 18.88 Ohms

Now that we have the total impedance, we can find the total current (I) using Ohm's law:

I = V/Z

where:
V = voltage = 120 Volts
Z = total impedance = 18.88 Ohms

Substituting these values into the formula, we get:

I = 120/18.88 = 6.36 Amps

So, the total current in the circuit is approximately 6.36 Amps.

Knowee AI · Accepted Answer

To find the total current in the circuit, we first need to find the total impedance (Z) of the circuit. Since the resistor (R), inductor (L), and capacitor (C) are connected in parallel, we can use the formula for total impedance in a parallel RLC circuit:

1/Z^2 = 1/R^2 + (1/Xl - 1/Xc)^2

where:
R = resistance = 20 Ohms
Xl = inductive reactance = 59 Ohms
Xc = capacitive reactance = 35 Ohms

Substituting these values into the formula, we get:

1/Z^2 = 1/(20)^2 + (1/59 - 1/35)^2
1/Z^2 = 0.0025 + 0.000306
1/Z^2 = 0.002806

Taking the square root of both sides to solve for Z, we get:

Z = 1/√0.002806 = 18.88 Ohms

Now that we have the total impedance, we can find the total current (I) using Ohm's law:

I = V/Z

where:
V = voltage = 120 Volts
Z = total impedance = 18.88 Ohms

Substituting these values into the formula, we get:

I = 120/18.88 = 6.36 Amps

So, the total current in the circuit is approximately 6.36 Amps.

A resistor, a pure inductor and a capacitor are connected in parallel to a 120 Volt, 60 HZ supply. The resistor has a resistance of 20 Ohms, the inductor an inductive reactance of 59 Ohms and the capacitor a capacitive reactance of 35 Ohms.What is the total current in the circuit?

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