A single-phase motor and an incandescent lamp are connected in parallel to a 120 Volt, 60 HZ supply. The lamp has hot resistance of 100 Ohms. The motor has a resistance of 20 Ohms and an inductive reactance of 60 Ohms.What is the total circuit power?
Question
A single-phase motor and an incandescent lamp are connected in parallel to a 120 Volt, 60 HZ supply. The lamp has hot resistance of 100 Ohms. The motor has a resistance of 20 Ohms and an inductive reactance of 60 Ohms.What is the total circuit power?
Solution
To find the total circuit power, we need to calculate the power consumed by both the lamp and the motor separately, then add them together.
Step 1: Calculate the power consumed by the lamp. The power consumed by the lamp (P_lamp) can be calculated using Ohm's law (P = V^2 / R), where V is the voltage and R is the resistance.
P_lamp = V^2 / R_lamp = 120^2 / 100 = 144 Watts
Step 2: Calculate the power consumed by the motor. The power consumed by the motor (P_motor) can be calculated using the formula P = V^2 / Z, where Z is the impedance. The impedance of the motor can be calculated using the formula Z = sqrt(R^2 + X^2), where R is the resistance and X is the reactance.
Z_motor = sqrt(20^2 + 60^2) = 64 Ohms
P_motor = V^2 / Z_motor = 120^2 / 64 = 225 Watts
Step 3: Calculate the total circuit power. The total circuit power (P_total) is the sum of the power consumed by the lamp and the motor.
P_total = P_lamp + P_motor = 144 + 225 = 369 Watts
So, the total circuit power is 369 Watts.
Similar Questions
What is the total current in a circuit consisting of six 100-watt lamps connected in parallel to a 120-volt source?A 5 AB 20 AC 600 AD 12 000 A
A resistor, a pure inductor and a capacitor are connected in parallel to a 120 Volt, 60 HZ supply. The resistor has a resistance of 20 Ohms, the inductor an inductive reactance of 59 Ohms and the capacitor a capacitive reactance of 35 Ohms.What is the total current in the circuit?
The hot resistance of a 240 V filament lamp is 960Ω. Find the current taken by the lamp and its power rating
A coil of resistance 10Ω and inductance 140mH is connected in parallel with a 260Ωresistor across a 230V, 50Hz supply. Calculate the following(i) Current in the coil and phase angle of this current (4 Marks)(ii) Supply current (4 Marks)(iii) Circuit impedance (3 Marks)(iv) Power factor (3 Marks)(v) Power consumed
The total power dissipated in a parallel circuit is equal to thepower in the largest resistorpower in the smallest resistoraverage of the power in all resistorssum of the power in all resistors
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.