A capacitor with capacitance C = 4.29 ⋅ 10−6 F𝐶 = 4.29 · 10-6 F is connected to an AC power source having a peak value of 14.1 V and f = 151 Hz. Find the reactance of the capacitor. Ω Calculate the maximum current in the circuit. A
Question
A capacitor with capacitance C = 4.29 ⋅ 10−6 F𝐶 = 4.29 · 10-6 F is connected to an AC power source having a peak value of 14.1 V and f = 151 Hz. Find the reactance of the capacitor. Ω Calculate the maximum current in the circuit. A
Solution
The reactance (Xc) of a capacitor in an AC circuit is given by the formula:
Xc = 1/(2πfC)
where: f is the frequency, and C is the capacitance.
Substituting the given values:
Xc = 1/(2π151 Hz4.29*10^-6 F)
Calculate the above expression to find the reactance.
The maximum current (Imax) in the circuit can be found using Ohm's law:
Imax = Vmax/Xc
where: Vmax is the peak voltage.
Substitute the given peak voltage and the calculated reactance into the formula:
Imax = 14.1 V / Xc
Calculate the above expression to find the maximum current.
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