The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); ans. 7 6 5 7 6 6 5 5 7 7 6 7
Question
The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i);
ans. 7 6 5
7 6 6
5 5 7
7 6 7
Solution
The output of this code is undefined. This is because the order of evaluation of arguments in a function call is not specified in the C language standard. Therefore, the behavior of this code may vary between different compilers or even different runs of the same compiler. It's generally considered bad practice to write code that depends on this kind of undefined behavior.
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