A resistive network consists of a conductance of 0.2 mS and a voltage source connected to the network is 30 V. What will be the power in mW?
Question
A resistive network consists of a conductance of 0.2 mS and a voltage source connected to the network is 30 V. What will be the power in mW?
Solution 1
To find the power in the resistive network, we can use the formula P = V^2 * G, where P is the power, V is the voltage, and G is the conductance.
Given: V = 30 V G = 0.2 mS = 0.2 * 10^-3 S (since 1 mS = 10^-3 S)
Substituting these values into the formula:
P = (30)^2 * 0.2 * 10^-3 P = 900 * 0.2 * 10^-3 P = 180 * 10^-3 P = 0.18 W
Since 1 W = 1000 mW, we convert the power from W to mW:
P = 0.18 * 1000 P = 180
Solution 2
To find the power in the resistive network, we can use the formula P = V^2 * G, where P is the power, V is the voltage, and G is the conductance.
Step 1: Identify the given values. The voltage V is given as 30 V and the conductance G is given as 0.2 mS or 0.2 * 10^-3 S (since 1 mS = 10^-3 S).
Step 2: Substitute the given values into the formula. P = (30 V)^2 * 0.2 * 10^-3 S = 900 V^2 * 0.2 * 10^-3 S
Step 3: Calculate the power. P = 180 V^2 * 10^-3 S = 180 mW (since 1 V^2*S = 1 W = 10^3 mW)
So, the power in the resistive network is 180 mW.
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