50 mA of current flows through a 10 kΩ resistor. How much power is dissipated?
Question
50 mA of current flows through a 10 kΩ resistor. How much power is dissipated?
Solution
The power P dissipated in an electrical circuit is given by the formula:
P = I^2 * R
where:
- P is the power in watts,
- I is the current in amperes, and
- R is the resistance in ohms.
Given that the current is 50 mA (which is 0.05 A) and the resistance is 10 kΩ (which is 10,000 Ω), we can substitute these values into the formula to find the power dissipated:
P = (0.05 A)^2 * 10,000 Ω = 0.0025 A^2 * 10,000 Ω = 25 watts.
So, the power dissipated is 25 watts.
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