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A started a work and left after working for 2 days. Then B was called and he finished the work in 9 days. Had A left the work after working for 3 days, B would have finished the remaining work in 6 days. In how many days can each of them, working alone finish the whole work?Options2.5 days, 7.5 days5 days, 8.5 days5 days, 15 daysNone of these

Question

A started a work and left after working for 2 days. Then B was called and he finished the work in 9 days. Had A left the work after working for 3 days, B would have finished the remaining work in 6 days. In how many days can each of them, working alone finish the whole work?Options2.5 days, 7.5 days5 days, 8.5 days5 days, 15 daysNone of these

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Solution

This problem can be solved using the concept of work and efficiency in time and work problems.

Step 1: Let's denote the total work to be done as 1 unit.

Step 2: From the problem, we know that A works for 2 days and B finishes the remaining work in 9 days. This can be written as: 2A + 9B = 1 ---- (equation 1)

Step 3: The problem also states that if A had worked for 3 days, B would have finished the remaining work in 6 days. This can be written as: 3A + 6B = 1 ---- (equation 2)

Step 4: Now, we have two equations with two variables. We can solve these equations to find the values of A and B.

Subtract equation 2 from equation 1, we get: -1A + 3B = 0 => A = 3B ---- (equation 3)

Step 5: Substitute equation 3 in equation 1, we get: 2(3B) + 9B = 1 => 15B = 1 => B = 1/15

Step 6: Substitute B = 1/15 in equation 3, we get: A = 3(1/15) = 1/5

So, A can finish the work in 5 days and B can finish the work in 15 days. Therefore, the answer is 5 days, 15 days.

This problem has been solved

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