What is the issue with the following operator overloading code? #include <iostream> class Complex { public: int real, imag; Complex(int r = 0, int i = 0) : real(r), imag(i) {} Complex operator+(const Complex& c) { Complex temp; temp.real = real + c.real; temp.imag = imag + c.imag; return temp; } }; int main() { Complex a(1, 2), b(3, 4), c; c = a + b; std::cout << "Sum: " << c.real << " + " << c.imag << "i" << std::endl; return 0; } (2 Points) a) No issue b) Missing return type in operator+ c) Incorrect addition logic d) Missing const in operator+ parameter

When an operator is overloaded it means that:

What is the issue with the following operator overloading code? #include <iostream> class Complex { public: int real, imag; Complex(int r = 0, int i = 0) : real(r), imag(i) {} Complex operator+(const Complex& c) { Complex temp; temp.real = real + c.real; temp.imag = imag + c.imag; return temp; } }; int main() { Complex a(1, 2), b(3, 4), c; c = a + b; std::cout << "Sum: " << c.real << " + " << c.imag << "i" << std::endl; return 0; } (2 Points) a) No issue b) Missing return type in operator+ c) Incorrect addition logic d) Missing const in operator+ parameter

In Python, operator overloading is achieved using:

Explain operator overloading with the implementation of Complex numbers.

When an operator is overloaded it means that: A. the same operator may perform more than one task B. you cannot use it in Java because it will get the compiler confused C. it can be used to concatenate two or more operators D. it has a lot of work