In the figure, there is a conducting wire having current i and which has a shape of closed half ellipse [x2a2+y2 b2=1] is kept in a uniform magnetic field B as shown. The magnitude of magnetic dipole moment of loop and torque acting on it are-
Question
In the figure, there is a conducting wire having current i and which has a shape of closed half ellipse [x2a2+y2 b2=1] is kept in a uniform magnetic field B as shown. The magnitude of magnetic dipole moment of loop and torque acting on it are-
Solution
To find the magnitude of the magnetic dipole moment of the loop, we can use the formula:
μ = iA
where μ is the magnetic dipole moment, i is the current flowing through the loop, and A is the area enclosed by the loop.
In this case, the loop has the shape of a closed half ellipse, given by the equation x^2/a^2 + y^2/b^2 = 1. To find the area enclosed by the loop, we can integrate the equation over the appropriate limits.
Let's assume that the loop lies in the xy-plane, with the major axis along the x-axis and the minor axis along the y-axis. The limits of integration for y will be -b to b, and for x, we can solve the equation for x in terms of y to get the limits.
Solving the equation x^2/a^2 + y^2/b^2 = 1 for x, we get:
x = ± a * sqrt(1 - y^2/b^2)
So the limits of integration for x will be -a * sqrt(1 - y^2/b^2) to a * sqrt(1 - y^2/b^2).
Now, we can calculate the area enclosed by the loop by integrating the equation over the given limits:
A = ∫[from -b to b] ∫[from -a * sqrt(1 - y^2/b^2) to a * sqrt(1 - y^2/b^2)] dx dy
Once we have the value of A, we can calculate the magnitude of the magnetic dipole moment using the formula μ = iA.
To find the torque acting on the loop, we can use the formula:
τ = μ x B
where τ is the torque, μ is the magnetic dipole moment, and B is the uniform magnetic field.
By taking the cross product of μ and B, we can find the direction and magnitude of the torque acting on the loop.
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