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The plane of a 5.0 cm x 8.0 cm rectangular loop of wire is parallel to a 0.19-T magnetic field.The loop carries a current of 6.2 A.(a) What torque acts on the loop?(b) What is the magnetic moment of the loop?(c) What is the maximum torque that can be obtained with the same total length of wirecarrying the same current in this magnetic field?

Question

The plane of a 5.0 cm x 8.0 cm rectangular loop of wire is parallel to a 0.19-T magnetic field.The loop carries a current of 6.2 A.(a) What torque acts on the loop?(b) What is the magnetic moment of the loop?(c) What is the maximum torque that can be obtained with the same total length of wirecarrying the same current in this magnetic field?

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Solution

(a) The torque (τ) on a current loop in a magnetic field is given by the equation τ = μBsinθ, where μ is the magnetic moment, B is the magnetic field, and θ is the angle between the magnetic field and the normal to the plane of the loop. Since the plane of the loop is parallel to the magnetic field, θ = 0 degrees and sinθ = 0. Therefore, the torque on the loop is 0.

(b) The magnetic moment (μ) of a current loop is given by the equation μ = IAn, where I is the current, A is the area of the loop, and n is the number of turns in the loop. Since the loop is a single turn, n = 1. The area of the loop is A = length x width = 5.0 cm x 8.0 cm = 40 cm^2 = 0.004 m^2. Therefore, the magnetic moment of the loop is μ = IAn = 6.2 A x 0.004 m^2 x 1 = 0.0248 Am^2.

(c) The maximum torque (τ_max) that can be obtained with the same total length of wire carrying the same current in this magnetic field is when the plane of the loop is perpendicular to the magnetic field, i.e., θ = 90 degrees and sinθ = 1. Therefore, τ_max = μB = 0.0248 Am^2 x 0.19 T = 0.004712 Nm.

This problem has been solved

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