The half-life of carbon-14, 14C, is approximately 5,730 years. A bone fragment is estimated to have originally contained 4 milligrams of 14C.Write the exponential decay equation where A is the amount (in mg) of carbon-14 remaining in the bone fragment after t years.

The half-life of carbon 14 is 5,730 years. Approximately, how old is a bone that has 70% of its original carbon 14?Question 3Select one:a.7,500 yearsb.7,000 yearsc.6,500 yearsd.6,000 yearse.Less than 6,000 years

Carbon-14 is a radioactive nucleus with a half-life of 5760 years. In livingmatter the amount of carbon-14 decays at a rate of 15.3 decay events perminute per gram of carbon. A fossil is analysed and found to have a carbon-14 decay rate of 7.70 decay events per minute per gram of carbon. How oldis the fossil?

The half life for the radioactive decay of carbon-14 to nitrogen-14 is ×5.73103 years.Suppose nuclear chemical analysis shows that there is 0.590mmol of nitrogen-14 for every 1.000mmol of carbon-14 in a certain sample of rock. Calculate the age of the rock.Round your answer to 2 significant digits.

Select the correct answer.The amount of a radioactive substance remaining as it decays over time is 𝐴=𝐴0⁢(0.5)𝑡ℎ , where A represents the final amount, 𝐴0 represents the original amount, t represents the number of years, and h represents the half-life of the substance.Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14 to decay to 10 percent of its original amount? A. 16,396 years B. 19,035 years C. 28,650 years D. 8,267 years

The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.