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The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

Question

The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

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Solution

To estimate the age of the sample, we can use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where: N is the final quantity of the substance N0 is the initial quantity of the substance t is the time that has passed T is the half-life of the substance

In this case, we know that N/N0 is 80%, or 0.8, and T is 5730 years. We want to solve for t.

0.8 = (1/2)^(t/5730)

To solve for t, we can take the natural logarithm of both sides:

ln(0.8) = (t/5730) * ln(1/2)

Then, solve for t:

t = 5730 * ln(0.8) / ln(1/2)

This gives us t ≈ 1600 years. So, the archaeological artifact is approximately 1600 years old.

This problem has been solved

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