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The following instruction is executed. Determine the address which is read:1 LDR R0 ,[ R1 , R2 , LSL #2]The value of R1 = Decimal 1000, and the value of R2 = Decimal 10

Question

The following instruction is executed. Determine the address which is read:1 LDR R0 ,[ R1 , R2 , LSL #2]The value of R1 = Decimal 1000, and the value of R2 = Decimal 10

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Solution

The instruction given is an ARM assembly language instruction. It's a Load Register (LDR) instruction with a flexible second operand.

Here's how to determine the address that is read:

  1. First, understand the instruction: LDR R0 ,[ R1 , R2 , LSL #2]. This instruction means load into register R0 the value at the address computed by adding the value in R1 and the value in R2 left shifted by 2.

  2. Given that R1 = 1000 and R2 = 10, we need to compute the effective address.

  3. The left shift operation (LSL #2) on R2 means we multiply R2 by 2^2 (or 4). So, R2 LSL #2 = 10 * 4 = 40.

  4. Now, add this result to the value in R1 to get the effective address: R1 + (R2 LSL #2) = 1000 + 40 = 1040.

So, the address that is read by the instruction is 1040.

This problem has been solved

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