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ldr r4, [r2, r3]  str r4, [r0]What happens as a result of these two lines?*Contents of memory address in r0 are copied to address r2+r3Sum of contents of r2 and r3 are copied to address in r0Sum of contents of r2 and r3 are copied to address in r4Contents of memory address given by r2+r3 are copied to address in r0

Question

ldr r4, [r2, r3]  str r4, [r0]What happens as a result of these two lines?*Contents of memory address in r0 are copied to address r2+r3Sum of contents of r2 and r3 are copied to address in r0Sum of contents of r2 and r3 are copied to address in r4Contents of memory address given by r2+r3 are copied to address in r0

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Solution

The correct answer is: "Contents of memory address given by r2+r3 are copied to address in r0"

Here's the step by step explanation:

  1. The first instruction "ldr r4, [r2, r3]" loads the contents of the memory address calculated by adding the values in registers r2 and r3 into register r4.

  2. The second instruction "str r4, [r0]" stores the contents of register r4 into the memory address specified by register r0.

So, the overall effect of these two instructions is to copy the contents of the memory address given by r2+r3 to the memory address in r0.

This problem has been solved

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