using partial fractions, integrate (4x^3+2x^2+3x+2)/(x^2(x^2+1))
Question
using partial fractions, integrate (4x^3+2x^2+3x+2)/(x^2(x^2+1))
Solution
Sure, let's solve this step by step.
Step 1: Decompose the fraction into partial fractions
The given fraction is (4x^3+2x^2+3x+2)/(x^2(x^2+1)). We can decompose this into partial fractions of the form:
A/x + B/x^2 + (Cx + D)/(x^2 + 1)
Step 2: Find the values of A, B, C, and D
To find the values of A, B, C, and D, we equate the original fraction to the decomposed form and compare coefficients on both sides.
4x^3+2x^2+3x+2 = Ax(x^2+1) + B*(x^2+1) + (Cx + D)*x^2
By comparing coefficients, we get the following system of equations:
A + C = 0 (coefficient of x^3) A + B + D = 2 (coefficient of x^2) A + C = 3 (coefficient of x) B = 2 (constant term)
Solving this system of equations, we get A = 1, B = 2, C = -1, D = -1.
Step 3: Integrate the decomposed fractions
Now, we integrate each of the decomposed fractions separately:
∫(4x^3+2x^2+3x+2)/(x^2(x^2+1)) dx = ∫(1/x) dx + ∫(2/x^2) dx + ∫((-x - 1)/(x^2 + 1)) dx
= ln|x| - 2/x - arctan(x) + C
So, the integral of (4x^3+2x^2+3x+2)/(x^2(x^2+1)) is ln|x| - 2/x - arctan(x) + C.
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