What will be the output of the following C program?#include<stdio.h>int main(){     int a[5] = {5, 3, 15, 20, 25};     int i, j, m;     i = ++a[1];     j = a[1]++;     m = a[i++];     printf("%d, %d, %d", i, j, m);     return 0;}

The output of the given C program will be "5, 4, 20".

Here's the step-by-step explanation:

1. The array a is initialized with the values {5, 3, 15, 20, 25}.

2. i = ++a[1]; This line increments the value at a[1] (which is 3) by 1, making it 4. The ++ before a[1] means the increment happens before the assignment, so i is also 4.

3. j = a[1]++; This line assigns the value at a[1] (which is now 4) to j, and then increments a[1] by 1, making it 5. The ++ after a[1] means the increment happens after the assignment, so j is 4.

4. m = a[i++]; This line assigns the value at a[i] (which is a[4] and equals 25) to m, and then increments i by 1, making it 5. However, because the ++ is after i, the increment happens after the assignment, so m is assigned the value at a[4] before i is incremented, which is 25.

5. printf("%d, %d, %d", i, j, m); This line prints the values of i, j, and m, which are 5, 4, and 25 respectively.

So, the output of the program is "5, 4, 25".