What will be the output of the following program?Note: This question helps in clearing AMCAT exam.12345678910#include <stdio.h>int main() { int c = 0, e = 0; for (e = 0;e < 5; e++) { c++; if (e == 3) break; } printf("%d",c);}

The output of the program will be 4.

Here's the step by step explanation:

1. The program starts with the declaration of two integer variables, c and e, both initialized to 0.

2. Then a for loop starts, which will run as long as e is less than 5.

3. In each iteration of the loop, the value of c is incremented by 1 and then there is a condition to check if e is equal to 3.

4. When e becomes 3 (which will be in the 4th iteration because e starts from 0), the break statement is encountered.

5. The break statement causes the control to exit from the loop immediately, regardless of whether the loop condition is true or false.

6. After the loop, the current value of c is printed. Since the loop has run 4 times before it was broken off, c has been incremented 4 times, so the output will be 4.