A house wife wishes to purchase three articles A, B and C from a sum of Rs.200.The unit prices of the articles A, B and C are Rs.20, Rs.35 and Rs.25 respectively.If she spends the entire amount by purchasing 5 numbers of articles of type C, what is the ratio of the number of articles purchased of type A to that of, type B?1 : 22 : 11 : 1None of these

First, let's calculate the total amount spent on article C.

The unit price of article C is Rs.25 and the housewife purchases 5 of these. So, the total amount spent on C is 25*5 = Rs.125.

She has a total of Rs.200. After spending Rs.125 on article C, she is left with 200 - 125 = Rs.75.

Now, let's find out how many of each of the other articles (A and B) she can buy with the remaining amount.

The unit price of article A is Rs.20 and that of B is Rs.35.

Let's assume she buys 'x' number of A articles and 'y' number of B articles.

So, the total amount spent on A and B would be 20x + 35y.

Since she only has Rs.75 left, we can set up the equation 20x + 35y = 75.

Without more information, we can't solve for exact values of x and y. However, we can see that she can't buy more than 3 articles of type A (as 420 = 80 which is more than 75) and she can't buy more than 2 articles of type B (as 335 = 105 which is more than 75).

So, the ratio of the number of articles of type A to type B can't be more than 3:2.

Therefore, the answer is "None of these".