A sum of money is divided among A, B, C and D in the ratio 3 : 5 : 7 : 11 respectively. If the share of C is Rs. 1668 more than the share of A, then what is the total amount of money of B and D together ?
Question
A sum of money is divided among A, B, C and D in the ratio 3 : 5 : 7 : 11 respectively. If the share of C is Rs. 1668 more than the share of A, then what is the total amount of money of B and D together ?
Solution
Sure, let's solve this step by step.
Step 1: Understand the ratios The ratio of the money divided among A, B, C, and D is 3:5:7:11. This means that for every 3 parts A gets, B gets 5 parts, C gets 7 parts, and D gets 11 parts.
Step 2: Calculate the difference between C and A's shares According to the problem, C's share is Rs. 1668 more than A's share. In terms of the ratio, C gets 7 parts and A gets 3 parts, so the difference is 4 parts. This means that 4 parts are equivalent to Rs. 1668.
Step 3: Find the value of 1 part If 4 parts are equivalent to Rs. 1668, then 1 part is equivalent to Rs. 1668 / 4 = Rs. 417.
Step 4: Calculate B and D's shares Now that we know the value of 1 part, we can calculate B and D's shares. B gets 5 parts and D gets 11 parts, so B's share is 5 * Rs. 417 = Rs. 2085 and D's share is 11 * Rs. 417 = Rs. 4587.
Step 5: Add B and D's shares The total amount of money B and D get together is Rs. 2085 + Rs. 4587 = Rs. 6672.
So, B and D together get Rs. 6672.
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