Two charges of 5Q and −2Q are situated at the points (3a,0) and (−5a,0) respectively. The electric flux through a sphere of radius ' 4a ' having center at origin is :
Question
Two charges of 5Q and −2Q are situated at the points (3a,0) and (−5a,0) respectively. The electric flux through a sphere of radius ' 4a ' having center at origin is :
Solution
The electric flux (Φ) through a closed surface in an electric field is given by Gauss's law, which states that the total electric flux through a closed surface is equal to 1/ε times the total charge enclosed by the surface. Here, ε is the permittivity of free space.
The total charge enclosed by the sphere is the sum of the charges of 5Q and -2Q, which is 3Q.
Therefore, the electric flux through the sphere is 1/ε times the total charge enclosed by the surface, which is 3Q/ε.
So, the electric flux through the sphere is 3Q/ε.
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