In a cuboid of dimension 2L×2L×L , a charge q is placed at the centre of the surface S having area of 4L2 . The flux through the opposite surface to S is given by

A charge q is placed at the centre of a cube, the magnitude of flux through one of its faces will be: ans. q q / 6 6qq / 3  Previous Marked for Review Next

An electric charge q is placed at one of the corner points of a cube of side a. What will bethe net outwards flux coming out of the cube due to the point charge?

Point charges of 2μC and -5μC is at an unspecified location inside a cube with a side of 50cm. Find the net electric flux through the surfaces of the cube.

The inward and outward electric flux from a closed surface are respectively 8 × 103 and 4 × 103 units. Then the net charge inside the closed surface is –– 4 × 103 coulomb4 × 103 coulomb–4 × 103 ε0 coulomb

Net electric flux through a cube is the sum of fluxes through its six faces. Consider a cube as shown in figure,having sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00 × 103NC-1 and isparallel to the xy plane at an angle of 37o measured from the +x -axis towards the +y -axis.(i) Electric flux passing through surface S6 isa) -24 Nm2 C-1 b) 32 Nm2 C-1 c) -32 Nm2 C-1 d) 24 Nm2 C-1(ii) Electric flux passing through surface S1 isa) -32 Nm2 C-1 b) -24 Nm2 C-1 c) 32 Nm2 C-1 d) 24 Nm2 C-1(iii) The surfaces that have zero flux area) S2 and S4 b) S3 and S6 c) S1 and S2 d) S1 and S3(iv) The total net electric flux through all faces of the cube isa) 24 Nm2 C-1 b) 8 Nm2 C-1 c) -8 Nm2 C-1 d) zero30. Read the text carefully and answer the question.A transformer is essentially an a c. device. lt cannot work on d.c. It changes alternating voltages or currents.It does not affect the frequency of a.c. It is based on the phenomenon of mutual induction. A transformeressentially consists of two coils of insulated copper wire having a different number of turns and wound onthe same soft iron core.The number of turns in the primary and secondary coils of an ideal transformer are 2000 and 50 respectively.The primary coil is connected to the main supply of 120 V and secondary coil is connected to a bulb ofresistance 0.6 Ω.1. What will be the value of voltage across the secondary coil'?2. Find the value of the current in the bulb.3. What Will be the value of current in the primary coil'?ORCalculate the power in primary coi