1𝑞+2𝑚−10=0 and 6𝑞+2𝑚−20=0𝑞=3 ; 𝑚=3𝑞=3 ; 𝑚=5𝑞=2 ; 𝑚=4𝑞=1 ; 𝑚=

It seems like there's some confusion in your question as it contains multiple equations and values for variables q and m. However, I'll try to help you solve the first two equations you provided:

1. 1q + 2m - 10 = 0
2. 6q + 2m - 20 = 0

Let's solve these two equations step by step:

Step 1: Rewrite the equations:

q + 2m = 10 6q + 2m = 20

Step 2: Divide the second equation by 2 to simplify:

3q + m = 10

Now we have two new equations:

q + 2m = 10 3q + m = 10

Step 3: Subtract the second equation from the first:

(q + 2m) - (3q + m) = 10 - 10 -2q + m = 0

Step 4: Solve for m:

m = 2q

Step 5: Substitute m = 2q into the first equation:

q + 2(2q) = 10 q + 4q = 10 5q = 10

Step 6: Solve for q:

q = 10 / 5 q = 2

Step 7: Substitute q = 2 into m = 2q:

m = 2 * 2 m = 4

So, the solution for the system of equations is q = 2 and m = 4.