Find the value of variables :1𝑞+2𝑚−10=0 and 6𝑞+2𝑚−20=0𝑞=3 ; 𝑚=3𝑞=3 ; 𝑚=5𝑞=2 ; 𝑚=4𝑞=1 ; 𝑚=

It seems like there is some confusion in your question as you have provided multiple values for the variables q and m. However, I can show you how to solve the system of equations you provided:

1q + 2m - 10 = 0 and 6q + 2m - 20 = 0

First, let's rewrite these equations in a more standard form:

q + 2m = 10 6q + 2m = 20

We can simplify the second equation by dividing every term by 2:

3q + m = 10

Now we have a system of two equations:

q + 2m = 10 3q + m = 10

We can solve this system by substitution or elimination. Let's use elimination. We can subtract the second equation from the first:

(q + 2m) - (3q + m) = 10 - 10

This simplifies to:

-2q + m = 0

So, m = 2q

Substitute m into the first equation:

q + 2(2q) = 10 q + 4q = 10 5q = 10 q = 2

Substitute q = 2 into the equation m = 2q:

m = 2*2