In neutral or alkaline solution, MnO−4MnO4- oxidises thiosulphate to

In neutral or alkaline solution, MnO4- oxidises thiosulphate to tetrathionate.

Here's the step by step process:

1. The reaction between MnO4- and thiosulphate (S2O3 2-) in a neutral or alkaline solution results in the formation of MnO2 and tetrathionate (S4O6 2-).

2. The balanced chemical equation for this reaction is:

   2 MnO4- + 5 S2O3 2- + H2O → 2 MnO2 + 5 S4O6 2- + 2 OH-

3. This reaction is an example of a redox reaction, where MnO4- is reduced to MnO2 and S2O3 2- is oxidised to S4O6 2-.

4. The MnO4- acts as an oxidising agent, meaning it accepts electrons from the S2O3 2- during the reaction.

5. The S2O3 2- acts as a reducing agent, meaning it donates electrons to the MnO4- during the reaction.

6. The end product of this reaction is tetrathionate (S4O6 2-).