What are the oxidation numbers of manganese in the following equation?KMnO4 → K2MnO4 + MnO4 + O2
Question
What are the oxidation numbers of manganese in the following equation?KMnO4 → K2MnO4 + MnO4 + O2
Solution
In the given equation, we have three compounds containing manganese (Mn): KMnO4, K2MnO4, and MnO4.
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KMnO4: In this compound, the oxidation number of K is +1 and O is -2. Let's assume the oxidation number of Mn is x. So, we have: K (+1) + Mn (x) + 4O (-2) = 0 Solving for x, we get x = +7. So, the oxidation number of Mn in KMnO4 is +7.
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K2MnO4: In this compound, the oxidation number of K is +1 and O is -2. Let's assume the oxidation number of Mn is y. So, we have: 2K (+1) + Mn (y) + 4O (-2) = 0 Solving for y, we get y = +6. So, the oxidation number of Mn in K2MnO4 is +6.
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MnO4: In this compound, the oxidation number of O is -2. Let's assume the oxidation number of Mn is z. So, we have: Mn (z) + 4O (-2) = 0 Solving for z, we get z = +8. So, the oxidation number of Mn in MnO4 is +8.
Therefore, the oxidation numbers of manganese in the given equation are +7, +6, and +8.
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