The binding energies of the nuclei of He, Li, C &  N are 28, 52, 90, 98 MeV respectively. Which of these is most stable. He  Li C N

The stability of a nucleus is determined by its binding energy per nucleon. The binding energy per nucleon is calculated by dividing the total binding energy by the number of nucleons (protons and neutrons) in the nucleus.

Here are the atomic numbers (number of protons) and mass numbers (number of protons + neutrons) for each element:

• Helium (He): Atomic number = 2, Mass number = 4
• Lithium (Li): Atomic number = 3, Mass number = 7
• Carbon (C): Atomic number = 6, Mass number = 12
• Nitrogen (N): Atomic number = 7, Mass number = 14

Now, let's calculate the binding energy per nucleon for each element:

• He: 28 MeV / 4 = 7 MeV/nucleon
• Li: 52 MeV / 7 = 7.43 MeV/nucleon
• C: 90 MeV / 12 = 7.5 MeV/nucleon
• N: 98 MeV / 14 = 7 MeV/nucleon

From these calculations, we can see that Carbon (C) has the highest binding energy per nucleon, which means it is the most stable nucleus among the given elements.