Events $A$A​ and $B$B​ are disjoint. Find $P\left(A\ \text{or}\ B\right)$P(A or B)​ when $P(A)=\frac{2}{3}$P(A)=23​​ and $P\left(B\right)=\frac{1}{5}$P(B)=15​​ .  Express your answer as a fraction in simplest form.$P\left(A\ \text{or}\ B\right)=$P(A or B)=​

Events $A$A​ and $B$B​ are disjoint. Find $P\left(A\ \text{or}\ B\right)$P(A or B)​ when $P(A)=0.3$P(A)=0.3​ and $P\left(B\right)=0.1$P(B)=0.1​ .$P\left(A\ \text{or}\ B\right)=$P(A or B)=​

We found that P(A and B) = 0.15. Since the probability that both events happen at the same time is not 0, it means that events A and B have some outcomes in common. Therefore, the events A and B are not mutually exclusive.To compute P(A or B) means that we wish to find the probability that either A happened or B happened. Since the events are not mutually exclusive, we can apply the general addition rule for events. Recall that P(A) = 0.3 and P(B) = 0.5.P(A or B)  =  P(A) + P(B) − P(A and B) =  0.3 + 0.5 −  =

Given that for two events A and B, P (A) = 3/5, P (B) = 2/3 and P (A) = 3/4, what is P (A/B)?(a) 0.655(b) 13/60(c) 31/60(d) 0.775

A and B are mutually exclusive events. P(A) = 0.60 and P(B) = 0.30. What is P(A or B)?A.0.15B.0.90C.0.72D.0.18

It is known that P(A) = 0.3, P(B) = 0.65, P(A and B) = 0.15 and P(A or B) = 0.8. Given that A occurs, what is the probability that B also occurs