Events $A$A and $B$B are disjoint. Find $P\left(A\ \text{or}\ B\right)$P(A or B) when $P(A)=0.3$P(A)=0.3 and $P\left(B\right)=0.1$P(B)=0.1 .$P\left(A\ \text{or}\ B\right)=$P(A or B)=
Question
Events A and B are disjoint. Find P(A or B) when P(A)=0.3 and P(B)=0.1 .P(A or B)=
Solution
The events A and B are disjoint, which means they cannot both occur at the same time. Therefore, the probability of either A or B occurring is simply the sum of their individual probabilities.
So, we have:
P(A or B) = P(A) + P(B)
Substituting the given values:
P(A or B) = 0.3 + 0.1 = 0.4
So, the probability of either event A or event B occurring is 0.4.
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