Consider an electron moving with a speed of 8.60 106 m/s at right angles to a constant magnetic field, with B = 1.4 T. What is the radius of the circular path of the electron?
Question
Consider an electron moving with a speed of 8.60 106 m/s at right angles to a constant magnetic field, with B = 1.4 T. What is the radius of the circular path of the electron?
Solution
The radius of the circular path of an electron moving in a magnetic field can be calculated using the formula:
r = mv / (qB)
where:
- m is the mass of the electron,
- v is the speed of the electron,
- q is the charge of the electron, and
- B is the magnetic field strength.
Given:
- m = 9.11 x 10^-31 kg (mass of an electron),
- v = 8.60 x 10^6 m/s (given in the problem),
- q = 1.60 x 10^-19 C (charge of an electron), and
- B = 1.4 T (given in the problem).
Substituting these values into the formula, we get:
r = (9.11 x 10^-31 kg * 8.60 x 10^6 m/s) / (1.60 x 10^-19 C * 1.4 T)
Solving this equation will give you the radius of the circular path of the electron.
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